Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 33

Answer

$6-3\sqrt{2}$

Work Step by Step

Rationalize the denominator by multiplying $2-\sqrt{2}$ to both the numerator and the denominator to have: $=\dfrac{6}{2+\sqrt{2}} \cdot \dfrac{2-\sqrt{2}}{2-\sqrt{2}} \\=\dfrac{12-6\sqrt{2}}{4-2} \\=\dfrac{12-6\sqrt{2}}{2} \\=6-3\sqrt{2}$
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