Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises - Page R-29: 33



Work Step by Step

Rationalize the denominator by multiplying $2-\sqrt{2}$ to both the numerator and the denominator to have: $=\dfrac{6}{2+\sqrt{2}} \cdot \dfrac{2-\sqrt{2}}{2-\sqrt{2}} \\=\dfrac{12-6\sqrt{2}}{4-2} \\=\dfrac{12-6\sqrt{2}}{2} \\=6-3\sqrt{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.