## Calculus with Applications (10th Edition)

$x^2yz^2\sqrt[4]{y^3z^3}$
Simplify by factoring the radicand so that one factor is a perfect fourth power to have: $=\sqrt[4]{x^8y^4z^8(y^3z^3)} \\=x^2yz^2\sqrt[4]{y^3z^3}$