Answer
$x^2yz^2\sqrt[4]{y^3z^3}$
Work Step by Step
Simplify by factoring the radicand so that one factor is a perfect fourth power to have:
$=\sqrt[4]{x^8y^4z^8(y^3z^3)}
\\=x^2yz^2\sqrt[4]{y^3z^3}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises - Page R-29: 18
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