Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 31

Answer

$-3-3\sqrt2$

Work Step by Step

Rationalize the denominator by multiplying $1+\sqrt{2}$ to both the numerator and the denominator to have: $=\dfrac{3}{1-\sqrt{2}} \cdot \dfrac{1+\sqrt{2}}{1+\sqrt{2}} \\=\dfrac{3+3\sqrt{2}}{1-2} \\=\dfrac{3+3\sqrt{2}}{-1} \\=-3-3\sqrt2$
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