## Calculus with Applications (10th Edition)

$\dfrac{\sqrt{10}}{2}$
Rationalize the denominator by multiplying $\sqrt{10}$ to both the numerator and the denominator to have: $=\dfrac{5}{\sqrt{10}} \cdot \dfrac{\sqrt{10}}{\sqrt{10}} \\=\dfrac{5\sqrt{10}}{10}$ Cancel the common factor $5$ to have: $=\dfrac{\sqrt{10}}{2}$