# Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises - Page R-29: 17

$4xy^2z^3\sqrt[3]{2y^2}$

#### Work Step by Step

Simplify by factoring the radicand so that one factor is a perfect cube to have: $=\sqrt[3]{64x^3y^6z^9(2y^2)} \\=4xy^2z^3\sqrt[3]{2y^2}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.