Answer
$4xy^2z^3\sqrt[3]{2y^2}$
Work Step by Step
Simplify by factoring the radicand so that one factor is a perfect cube to have:
$=\sqrt[3]{64x^3y^6z^9(2y^2)}
\\=4xy^2z^3\sqrt[3]{2y^2}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises - Page R-29: 17
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