Answer
a. 29.88;
b. $66.5
Work Step by Step
a. $P=\int ^{10}_{0} 25t.e^{-0.08t}=25\int ^{10}_{0} t.e^{-0.08t}=25 (-12.5te^{-0.08t}-156.25e^{-0.08t})|^{10}_{0} \approx 29.88$
b. $A=e^{(0.08)10}\int^{10}_{0}25te^{-0.08t}dt = e^{0.8}.25\int^{10}_{0}te^{-0.08t}dt=e^{0.8}.25.(-12.5te^{-0.08t}-156.25e^{-0.08t}|^{10}_{0}) \approx 66.5$
