Answer
a. 6911.5;
b. $15381.9.
Work Step by Step
a. $P=\int ^{10}_{0} 800e^{0.05t}.e^{-0.08t}=800\frac{e^{-0.03t}}{-0.03}|^{10}_{0}=\frac{-800}{0.03}(e^{-0.3}-1) \approx 6911.5 $
b. $A=e^{(0.08)10}\int^{10}_{0}800e^{0.05t}.e^{-0.08t}dt = e^{0.8}.800\int^{10}_{0}e^{-0.03t}dt=e^{0.8}.800.\frac{1}{-0.03}(e^{-0.03t}|^{10}_{0}) \approx 15381.9$
