Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 8 - Further Techniques and Applications of Integration - 8.3 Continuous Money Flow - 8.3 Exercises - Page 447: 7

Answer

a. 32968.4; b. $73372.4.

Work Step by Step

a. $P=\int ^{10}_{0} 5000e^{-0.01t}.e^{-0.08t}=5000\frac{e^{-0.09t}}{-0.09}|^{10}_{0}=\frac{-5000}{0.09}(e^{-0.9}-1) \approx 32968.4 $ b. $A=e^{(0.08)10}\int^{10}_{0}5000e^{-0.01t}.e^{-0.08t}dt = e^{0.8}.5000\int^{10}_{0}e^{-0.09t}dt=e^{0.8}.5000.\frac{1}{-0.09}(e^{-0.09t}|^{10}_{0}) \approx 73372.4$
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