Answer
a. 1493.8;
b. $3324.5
Work Step by Step
a. $P=\int ^{10}_{0} 50t.e^{-0.08t}=50\int ^{10}_{0} t.e^{-0.08t}=50 (-12.5te^{-0.08t}-156.25e^{-0.08t})|^{10}_{0} \approx 1493.8$
b. $A=e^{(0.08)10}\int^{10}_{0}50te^{-0.08t}dt = e^{0.8}.50\int^{10}_{0}te^{-0.08t}dt=e^{0.8}.50.(-12.5te^{-0.08t}-156.25e^{-0.08t}|^{10}_{0}) \approx 3324.5$
