Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 8 - Further Techniques and Applications of Integration - 8.1 Integration by Parts - 8.1 Exercises - Page 433: 32

Answer

$\int_1^{20}udv=101$

Work Step by Step

Using integration by parts, $\int vdu =uv -\int u dv$ Therefore, $\int _1^{20}vdu =uv|_1^{20} -\int_1^{20}u dv=-1$ $\implies\int_1^{20} udv=uv|_1^{20} +1$ $\implies\int_1^{20}u dv = (15\times6)-(5\times (-2))+1=101$
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