#### Answer

$y' =-30x^{-4}-20x^{-5}-8$

#### Work Step by Step

In order to derivate this function you have to apply the power rule:
$\dfrac{d}{dx}(x^n)=nx^{n-1}$
$y' =10(-3)x^{-4}+5(-4)x^{-5}-8$
$y' =-30x^{-4}-20x^{-5}-8$

Published by
Pearson

ISBN 10:
0321749006

ISBN 13:
978-0-32174-900-0

$y' =-30x^{-4}-20x^{-5}-8$

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