Calculus with Applications (10th Edition)

$h'(x) =6x^5-12x^3+6x$
In order to derivate this function you have to apply the power rule: $\dfrac{d}{dx}(x^n)=nx^{n-1}$ But first let's rewrite the function Note: Remember that $(a-b)^3=(a-b)(a^2+ab+b^2)$ $h(x) = x^6-3x^4+3x^2-1$ then $h'(x) =6x^5-12x^3+6x$