Answer
$h'(x) =6x^5-12x^3+6x$
Work Step by Step
In order to derivate this function you have to apply the power rule:
$\dfrac{d}{dx}(x^n)=nx^{n-1}$
But first let's rewrite the function
Note: Remember that $(a-b)^3=(a-b)(a^2+ab+b^2)$
$h(x) = x^6-3x^4+3x^2-1$
then
$h'(x) =6x^5-12x^3+6x$
