Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 4 - Calculating the Derivative - 4.1 Techniques for Finding Derivatives - 4.1 Exercises: 22

Answer

$h'(x) =6x^5-12x^3+6x$

Work Step by Step

In order to derivate this function you have to apply the power rule: $\dfrac{d}{dx}(x^n)=nx^{n-1}$ But first let's rewrite the function Note: Remember that $(a-b)^3=(a-b)(a^2+ab+b^2)$ $h(x) = x^6-3x^4+3x^2-1$ then $h'(x) =6x^5-12x^3+6x$
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