#### Answer

$y' = 12x^3-18x^2+\dfrac{1}{4}x$

#### Work Step by Step

In order to derivate this function you have to apply the power rule:
$\dfrac{d}{dx}(x^n)=nx^{n-1}$
$y' = 3(4)x^3-6(3)x^2+\dfrac{1}{8}(2)x$
$y' = 12x^3-18x^2+\dfrac{1}{4}x$

Published by
Pearson

ISBN 10:
0321749006

ISBN 13:
978-0-32174-900-0

$y' = 12x^3-18x^2+\dfrac{1}{4}x$

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