Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 4 - Calculating the Derivative - 4.1 Techniques for Finding Derivatives - 4.1 Exercises: 7

Answer

$y' = 4x^{-1/2}+\dfrac{9}{2}x^{-1/4}$

Work Step by Step

In order to derivate this function you have to apply the power rule: $\dfrac{d}{dx}(x^n)=nx^{n-1}$ But first let's rewrite the function $y = 8x^{1/2}+6x^{3/4}$ $y' = 8(1/2)x^{-1/2}+6(\dfrac{3}{4})x^{-1/4}$ $y' = 4x^{-1/2}+\dfrac{9}{2}x^{-1/4}$
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