#### Answer

$f'(x) = 21x^{2.5}-5x^{-0.5} $

#### Work Step by Step

In order to derivate this function you have to apply the power rule:
$\dfrac{d}{dx}(x^n)=nx^{n-1}$
$f'(x) = 6(3.5)x^{2.5}-10(0.5)x^{-0.5} $
$f'(x) = 21x^{2.5}-5x^{-0.5} $

Published by
Pearson

ISBN 10:
0321749006

ISBN 13:
978-0-32174-900-0

$f'(x) = 21x^{2.5}-5x^{-0.5} $

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