Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 4 - Calculating the Derivative - 4.1 Techniques for Finding Derivatives - 4.1 Exercises - Page 207: 21


$g'(x) = 256x^3-192x^2+32x$

Work Step by Step

In order to derivate this function you have to apply the power rule: $\dfrac{d}{dx}(x^n)=nx^{n-1}$ But first let's rewrite the function Note: Remember that $(a-b)^2=a^2-2ab+b^2$ $g(x) = 64x^4-64x^3+16x^2$ then $g'(x) = 256x^3-192x^2+32x$
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