Answer
$-\frac{4}{5}$
Work Step by Step
We need to find the slope of the tangent line at $(3,-1)$.
We can do this by taking two points - for example $(3,-1)$ and $(-2,3)$ -, through which the aforesaid line passes through.
The slope $m$ is:
$m = \dfrac{y_2-y_1}{x_2-x_1} = \dfrac{3-(-1)}{(-2)-3} = -\dfrac{4}{5}$
