Answer
$2$
Work Step by Step
We need to find the slope of the tangent line at $(5,3)$.
We can do this by taking two points - for example $(5,3)$ and $(6,5)$ -, through which the aforesaid line passes through.
The slope $m$ is:
$m = \frac{y_2-y_1}{x_2-x_1} = \frac{5-3}{6-5} = 2$.