Answer
There is a discontinuity when $a=3$ or $a=-2$
Work Step by Step
We are given $j(x)=\ln|\frac{x+2}{x-3}|$
There is a discontinuity when $a=3$ or $a=-2$
$\lim\limits_{x \to -2}j(x)=-\infty$
$\lim\limits_{x \to 3}j(x)=\infty$
The limit $\lim\limits_{x \to 3}j(x)$ and $\lim\limits_{x \to -2}j(x)$ do not exist.