Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 3 - The Derivative - 3.2 Continuity - 3.2 Exercises - Page 147: 18


There is a discontinuity when $a=3$ or $a=-2$

Work Step by Step

We are given $j(x)=\ln|\frac{x+2}{x-3}|$ There is a discontinuity when $a=3$ or $a=-2$ $\lim\limits_{x \to -2}j(x)=-\infty$ $\lim\limits_{x \to 3}j(x)=\infty$ The limit $\lim\limits_{x \to 3}j(x)$ and $\lim\limits_{x \to -2}j(x)$ do not exist.
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