Answer
$$ k(x)=e^{\sqrt{x-1}} $$
The power of exponential function is square root function, and square root function is discontinuous wherever $x-1<0$. There is a discontinuity when $x<1$ .
So the function is discontinuous for $a<1$. The limit as $x$ approaches any $a<1$ does not exist because the function is undefined for $x<1$ .
Work Step by Step
$$ k(x)=e^{\sqrt{x-1}} $$
The power of exponential function is square root function, and square root function is discontinuous wherever $x-1<0$. There is a discontinuity when $x<1$ .
So the function is discontinuous for $a<1$. The limit as $x$ approaches any $a<1$ does not exist because the function is undefined for $x<1$ .
