Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 3 - The Derivative - 3.2 Continuity - 3.2 Exercises - Page 147: 17

Answer

There is a discontinuity when $a=1$ The limit $\lim\limits_{x \to 1}k(x)$ does not exist.

Work Step by Step

We are given $k(x)=\ln|\frac{x}{x-1}|$ There is a discontinuity when $a=1$ The limit $\lim\limits_{x \to 1}k(x)$ does not exist.
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