Answer
$$
y=\frac{2x^{2}+3}{x^{3}-1}
$$
The line with equation $x=1 $ as vertical asymptotic.
The line $y=0 $ is a horizontal asymptotic.
The y-intercept is -3
This is graph $C$.
Work Step by Step
$$
y=\frac{2x^{2}+3}{x^{3}-1}
$$
The value $x= 1$ makes the denominator 0, but not the numerator, so the line with equation
$$
x=1
$$
as vertical asymptotic.
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty} \frac{2x^{2}+3}{x^{3}-1} =0
$$
This means that the line $y=0 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is -3
This is graph $C$.
