Answer
$$
y=0.7 x^{5}-2.5 x^{4}-x^{3}+8 x^{2}+x+2
$$
The graph of $y=0.7 x^{5}-2.5 x^{4}-x^{3}+8 x^{2}+x+2 $ has the right end up, the left end down, at most four turning points, and a &y&-intercept of 2.
This is graph $H$.
Work Step by Step
$$
y=0.7 x^{5}-2.5 x^{4}-x^{3}+8 x^{2}+x+2
$$
The graph of $y=0.7 x^{5}-2.5 x^{4}-x^{3}+8 x^{2}+x+2 $ has the right end up, the left end down, at most four turning points, and a $y$-intercept of 2.
This is graph $H$.
