Answer
$$
y=\frac{-2x^{2}-3}{x^{2}-1}
$$
has the lines with equations $ x= 1 $ and $ x= -1 $ as vertical
asymptotic,
The line $y=-2 $ is a horizontal asymptotic.
The y-intercept is 3.
This is graph $A$.
Work Step by Step
$$
y=\frac{-2x^{2}-3}{x^{2}-1}
$$
The values $x= \pm 1$ makes the denominator 0, but not the numerator, so the lines with equations
$$
x=1 , \, x=-1
$$
as vertical asymptotic.
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y= \lim _{x \rightarrow \infty } \frac{-2x^{2}-3}{x^{2}-1} =- 2.
$$
This means that the line $y=-2 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is 3
This is graph $A$.
