Answer
$$
y=\frac{-2x^{2}-3}{x^{2}+1}
$$
Has no vertical asymptotic line.
The line $y=-2 $ is a horizontal asymptotic.
The y-intercept is -3
This is graph $E$.
Work Step by Step
$$
y=\frac{-2x^{2}-3}{x^{2}+1}
$$
has no vertical asymptotic line.
To find a horizontal asymptotic, let $x$ get larger and larger, so that
$$
y=\lim _{x \rightarrow \infty} \frac{-2x^{2}-3}{x^{2}+1} =-2
$$
This means that the line $y=-2 $ is a horizontal asymptotic.
When $x=0 $ the y-intercept is -3
This is graph $E$.
