## Calculus with Applications (10th Edition)

$$y=\frac{-2x^{2}-3}{x^{2}+1}$$ Has no vertical asymptotic line. The line $y=-2$ is a horizontal asymptotic. The y-intercept is -3 This is graph $E$.
$$y=\frac{-2x^{2}-3}{x^{2}+1}$$ has no vertical asymptotic line. To find a horizontal asymptotic, let $x$ get larger and larger, so that $$y=\lim _{x \rightarrow \infty} \frac{-2x^{2}-3}{x^{2}+1} =-2$$ This means that the line $y=-2$ is a horizontal asymptotic. When $x=0$ the y-intercept is -3 This is graph $E$.