Answer
$$
y=-x^{5}+4x^{4}+x^{3}-16 x^{2}+x+2
$$
The graph of $y=-x^{5}+4x^{4}+x^{3}-16 x^{2}+x+2$ has the right end down, the left end up, at most four turning points, and a $y$-intercept of 2
This is graph $A$.
Work Step by Step
$$
y=-x^{5}+4x^{4}+x^{3}-16 x^{2}+x+2
$$
The graph of $y=-x^{5}+4x^{4}+x^{3}-16 x^{2}+x+2$ has the right end down, the left end up, at most four turning points, and a $y$-intercept of 2
This is graph $A$.