## Calculus with Applications (10th Edition)

$\sin \frac{-7\pi}{6}=\frac{-1}{2}$
We are given $\sin \frac{-7\pi}{6}$ $\sin(\frac{-7\pi}{6}+\pi)=\sin(\frac{-\pi}{6})$ convert $\frac{\pi}{6}$ radians to degrees $\frac{\pi}{6}=\frac{\pi}{6}(\frac{180^\circ}{\pi})$ $\frac{\pi}{6}=30^\circ$ $\sin \frac{-7\pi}{6}=-(\sin 30^\circ)$ $\sin30^\circ=\frac{1}{2}$ so $\sin \frac{-7\pi}{6}=\frac{-1}{2}$