Answer
$sin 60^\circ =\frac{\sqrt 3}{2}$
$cot 60^\circ =\frac{1}{\sqrt 3}$
$csc 60^\circ =\frac{2}{\sqrt 3}$
Work Step by Step
From the table we have the following information:
$cos 60^\circ=\frac{1}{2}$
$tan 60^\circ=\sqrt 3$
$sec 60^\circ =2$
$\theta$ (in radians) $=\frac{\pi}{3}$
then, using the elementary trigonometric identities we obtain:
$sin 60^\circ =\frac{\sqrt 3}{2}$
$cot 60^\circ =\frac{1}{\sqrt 3}$
$csc 60^\circ =\frac{2}{\sqrt 3}$
