Answer
$tan 240^\circ=\sqrt 3$
$cot240^\circ =\frac{\sqrt 3}{3}$
Work Step by Step
From the table we have the following information:
$sin 240^\circ =-\frac{\sqrt 3}{2}$
$cos 240^\circ=-\frac{1}{2}$
$sec240^\circ =-2$
$csc240^\circ =\frac{-2\sqrt 3}{3}$
then, using the elementary trigonometric identities we obtain:
$tan 240^\circ=\sqrt 3$
$cot240^\circ =\frac{1}{\tan 240^\circ}=\frac{1}{3}=\frac{\sqrt 3}{3}$