Answer
$sin 150^\circ =\frac{1}{2}$
$sec 150^\circ =\frac{-2}{\sqrt 3}$
$cot150^\circ =-\sqrt 3$
Work Step by Step
From the table we have the following information:
$cos 150^\circ=-\frac{\sqrt 3}{2}$
$tan 150^\circ=\frac{-\sqrt 3}{3}$
$csc150^\circ =2$
then, using the elementary trigonometric identities we obtain:
$sin 150^\circ =\frac{1}{2}$
$sec 150^\circ =\frac{-2}{\sqrt 3}$
$cot150^\circ =\frac{1}{\tan 150^\circ}=-\sqrt 3$
