Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 13 - The Trigonometric Functions - 13.1 Definitions of the Trigonometric Functions - 13.1 Exercises - Page 678: 30


$sin 150^\circ =\frac{1}{2}$ $sec 150^\circ =\frac{-2}{\sqrt 3}$ $cot150^\circ =-\sqrt 3$

Work Step by Step

From the table we have the following information: $cos 150^\circ=-\frac{\sqrt 3}{2}$ $tan 150^\circ=\frac{-\sqrt 3}{3}$ $csc150^\circ =2$ then, using the elementary trigonometric identities we obtain: $sin 150^\circ =\frac{1}{2}$ $sec 150^\circ =\frac{-2}{\sqrt 3}$ $cot150^\circ =\frac{1}{\tan 150^\circ}=-\sqrt 3$
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