Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 13 - The Trigonometric Functions - 13.1 Definitions of the Trigonometric Functions - 13.1 Exercises - Page 678: 29

Answer

$tan 135^\circ=-\frac{\sqrt 2}{\sqrt 2}=-1$ $cot 135^\circ =\frac{1}{\tan 120^\circ}=-1$

Work Step by Step

From the table we have the following information: $sin 135^\circ =\frac{\sqrt 2}{2}$ $cos 135^\circ=-\frac{\sqrt 2}{2}$ $sec 135^\circ =-\sqrt 2$ $csc 135^\circ =\sqrt 2$ then, using the elementary trigonometric identities we obtain: $tan 135^\circ=-\frac{\sqrt 2}{\sqrt 2}=-1$ $cot 135^\circ =\frac{1}{\tan 120^\circ}=-1$
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