Answer
$\sec 225^\circ=-\sqrt 2$
Work Step by Step
We are given $\sec \frac{5\pi}{4}$
convert $\frac{5\pi}{4}$ to degrees
$\frac{5\pi}{4}$ radians=$\frac{5\pi}{4}(\frac{180^\circ}{\pi})$
$\frac{5\pi}{4}$ radians= $225^\circ$
$\sec 225^\circ=-sec 45^\circ $
and $\sec \theta=\frac{1}{\cos \pi}$
so $\sec 225^\circ=-\sqrt 2$