Answer
$${\text{the sequence is not geometric }}$$
Work Step by Step
$$\eqalign{
& {a_1} = 6,{a_2} = 8,{a_3} = 10,{a_4} = 12,{a_5} = 14,... \cr
& {\text{to verify that the sequence is geometric}}{\text{, divide each term except the first by }} \cr
& {\text{the preceding term}} \cr
& \frac{{{a_5}}}{{{a_4}}} = \frac{{14}}{{12}} = \frac{7}{6} \cr
& \frac{{{a_4}}}{{{a_3}}} = \frac{{12}}{{10}} = \frac{6}{5} \cr
& {\text{the ratio is not constant}}{\text{, so}} \cr
& {\text{the sequence is not geometric }} \cr} $$