Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 12 - Sequences and Series - 12.1 Geometric Sequences - 12.1 Exercises - Page 612: 1

Answer

See below.

Work Step by Step

We know that if a geometric series has a first term $a$ and a common ratio of $r$, the nth term can be expressed as $a_n=a\cdot r^{n-1}$ Hence here: $a_1=2\cdot 3^{1-1}=2\cdot 3^0=2$ $a_2=2\cdot 3^{2-1}=2\cdot 3^1=6$ $a_3=2\cdot 3^{3-1}=2\cdot 3^2=18$ $a_4=2\cdot 3^{4-1}=2\cdot 3^3=54$
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