Answer
See below.
Work Step by Step
We know that if a geometric series has a first term $a$ and a common ratio of $r$, the nth term can be expressed as $a_n=a\cdot r^{n-1}$
Hence here:
$a_1=2\cdot 3^{1-1}=2\cdot 3^0=2$
$a_2=2\cdot 3^{2-1}=2\cdot 3^1=6$
$a_3=2\cdot 3^{3-1}=2\cdot 3^2=18$
$a_4=2\cdot 3^{4-1}=2\cdot 3^3=54$