Answer
See below.
Work Step by Step
We know that if a geometric series has a first term $a$ and a common ratio of $r$, the nth term can be expressed as $a_n=a\cdot r^{n-1}$
Hence here:
$a_1=4\cdot 2^{1-1}=4\cdot 2^0=4$
$a_2=4\cdot 2^{2-1}=4\cdot 2^1=8$
$a_3=4\cdot 2^{3-1}=4\cdot 2^2=16$
$a_4=4\cdot 2^{4-1}=4\cdot 2^3=32$
$a_5=4\cdot 2^{5-1}=4\cdot 2^4=64$