Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 12 - Sequences and Series - 12.1 Geometric Sequences - 12.1 Exercises - Page 612: 2

Answer

See below.

Work Step by Step

We know that if a geometric series has a first term $a$ and a common ratio of $r$, the nth term can be expressed as $a_n=a\cdot r^{n-1}$ Hence here: $a_1=4\cdot 2^{1-1}=4\cdot 2^0=4$ $a_2=4\cdot 2^{2-1}=4\cdot 2^1=8$ $a_3=4\cdot 2^{3-1}=4\cdot 2^2=16$ $a_4=4\cdot 2^{4-1}=4\cdot 2^3=32$ $a_5=4\cdot 2^{5-1}=4\cdot 2^4=64$
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