Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 7 - Section 7.5 - Strategy for Integration - 7.5 Exercises - Page 508: 83

Answer

$$\int (2x^{2}+1)e^{x^{2}}dx=xe^{x^{2}}+C$$

Work Step by Step

$$\int (2x^{2}+1)e^{x^{2}}dx=\int x(2xe^{x^{2}})dx+\int e^{x^{2}}dx$$ $$=xe^{x^{2}}- \int e^{x^{2}}dx+\int e^{x^{2}}dx$$ $$=xe^{x^{2}}+C$$
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