Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 7 - Section 7.5 - Strategy for Integration - 7.5 Exercises - Page 508: 30



Work Step by Step

$$\int_{-1}^{2}\left|e^{x}-1\right|dx=\int_{-1}^{0}(1-e^{x})dx+\int_{0}^{2}(e^{x}-1)dx$$ $$=\left [x -e ^{x}\right ]_{-1}^{0}+\left [ e^{x}-x \right ]_{0}^{2}$$ $$=\frac{1}{e}+e^{2}-3$$
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