Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 7 - Section 7.5 - Strategy for Integration - 7.5 Exercises - Page 508: 37

Answer

$$\int_{0}^{\frac{\pi}{4}}\tan ^{3}\theta\sec ^{2}\theta d\theta=\frac{1}{4}$$

Work Step by Step

$$\int_{0}^{\frac{\pi}{4}}\tan ^{3}\theta\sec ^{2}\theta d\theta=\int_{0}^{\frac{\pi}{4}}\tan ^{3}\theta d\tan \theta$$ $$=\left [ \frac{\tan ^{4} \theta}{4} \right ]_{0}^{\frac{\pi}{4}}$$ $$=\frac{1}{4}$$
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