Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.1 - Maximum and Minimum Values - 4.1 Exercises - Page 283: 22

Answer

The absolute maximum is $f(0) = 1$ The absolute minimum is $f(-\pi) = f(\pi) = -1$ The local maximum is $f(0) = 1$ The local minima are $f(-\pi) = f(\pi) = -1$

Work Step by Step

$f(t) = cos~t,~~~~~-\frac{3\pi}{2} \leq t \leq \frac{3\pi}{2}$ The absolute maximum is $f(0) = 1$ The absolute minimum is $f(-\pi) = f(\pi) = -1$ The local maximum is $f(0) = 1$ The local minima are $f(-\pi) = f(\pi) = -1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.