## Calculus: Early Transcendentals 8th Edition

The absolute maximum is $f(3) = 4$. There is no local maximum. There is no absolute or local minimum.
$f(x) = \frac{1}{2}(3x-1)$, $~~x \leq 3$ We can rewrite the equation as follows: $f(x) = \frac{3}{2}x-\frac{1}{2}$ The slope is $\frac{3}{2}$ The y-intercept is $-\frac{1}{2}$ The absolute maximum is $f(3) = 4$