Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.1 - Maximum and Minimum Values - 4.1 Exercises - Page 283: 15

Answer

The absolute maximum is $f(3) = 4$. There is no local maximum. There is no absolute or local minimum.
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Work Step by Step

$f(x) = \frac{1}{2}(3x-1)$, $~~x \leq 3$ We can rewrite the equation as follows: $f(x) = \frac{3}{2}x-\frac{1}{2}$ The slope is $\frac{3}{2}$ The y-intercept is $-\frac{1}{2}$ The absolute maximum is $f(3) = 4$
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