Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.1 - Maximum and Minimum Values - 4.1 Exercises - Page 283: 16

Answer

The absolute maximum is $f(-2) = \frac{8}{3}$ There is no local maximum. There is no absolute or local minimum.

Work Step by Step

$f(x) = 2-\frac{1}{3}x$, $~~x \geq -2$ The slope is $-\frac{1}{3}$ The y-intercept is $2$ The x-intercept is $6$ The absolute maximum is $f(-2) = \frac{8}{3}$
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