Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.1 - Maximum and Minimum Values - 4.1 Exercises - Page 283: 28

Answer

There is no absolute maximum. The absolute minimum is $f(3) = -2$ There is no local minimum. There is no local maximum.
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Work Step by Step

$f(x) = 2x+1~~~~~$ if $0 \leq x \lt 1$ $f(x) = 4-2x~~~~~$ if $1 \leq x \leq 3$ There is no absolute maximum. The absolute minimum is $f(3) = -2$ There is no local minimum. There is no local maximum.
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