Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.1 - Maximum and Minimum Values - 4.1 Exercises - Page 283: 20

Answer

The absolute maximum is $f(\frac{\pi}{2}) = 1$ There is no local maximum. There is no absolute/local minimum.

Work Step by Step

$f(x) = sin~x$, $~~0 \lt x \leq \frac{\pi}{2}$ The absolute maximum is $f(\frac{\pi}{2}) = 1$ There is no local maximum. There is no absolute/local minimum.
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