Answer
The absolute minimum is: $f(1)=-1$
There is no absolute maximum.
There is no local maximum or local minimum.
See graph below.
Work Step by Step
$f(x) = x^2~~~~~~~~~~~$ if $-1 \leq x \leq 0$
$f(x) = 2-3x~~~~$ if $0 \lt x \leq 1$
The absolute minimum is: $f(1)=-1$
There is no absolute maximum.
There is no local maximum or local minimum.