## Calculus: Early Transcendentals 8th Edition

$g'(x)=\frac{1-2x}{x}$
Use the derivative of natural log and apply the chain rule: $g'(x)=\frac{1}{xe^{-2x}}\times(-2xe^{-2x}+e^{-2x})$ After simplifying: $g'(x)=\frac{1-2x}{x}$