Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.6 - Derivatives of Logarithmic Functions - 3.6 Exercises - Page 223: 21


$y^{\prime}=\frac{a \sec ^{2}(\ln (a x+b))}{a x+b}$

Work Step by Step

$y=\tan (\ln (a x+b))\\ y^{\prime}=\sec ^{2}(\ln (a x+b)) \times \frac{1}{a x+b} \times a\\ y^{\prime}=\frac{a \sec ^{2}(\ln (a x+b))}{a x+b}$
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