Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.6 - Derivatives of Logarithmic Functions - 3.6 Exercises - Page 223: 25


$y^{\prime \prime}=\sec ^{2} x$

Work Step by Step

$y=\ln |\sec x|\\ y^{\prime}=\frac{1}{\sec x} \times \sec x \tan x\\ y^{\prime}=\tan x\\ y^{\prime \prime}=\sec ^{2} x$
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