Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.6 - Derivatives of Logarithmic Functions - 3.6 Exercises - Page 223: 14


$P'(v)=\frac{v\ln v-v+1}{v(1-v)^2}$

Work Step by Step

$P(v)=\frac{\ln v}{1-v}\\ P'(v)=\frac{(1-v)(\frac{1}{v})-(\ln v)(-1)}{(1-v)^2}\\ P'(v)=\frac{\frac{1-v+v\ln v}{v}}{(1-v)^2}\\ P'(v)=\frac{v\ln v-v+1}{v(1-v)^2}$
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