Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.6 - Derivatives of Logarithmic Functions - 3.6 Exercises - Page 223: 16



Work Step by Step

$y=\ln|1+t-t^3|\\ y'=\frac{1}{1+t-t^3}\times(0+1-3t^2)\\ y'=\frac{1-3t^2}{1+t-t^3}$
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