Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 16 - Section 16.8 - Stokes'' Theorem - 16.8 Exercise - Page 1139: 1

Answer

$\iint_{H} curl F \cdot dS=\iint_{P} curl F \cdot dS=\iint_{C} F \cdot dr$; and $C$ is the circle $x^2+y^2=4$ oriented counter-clockwise.

Work Step by Step

Stokes' Theorem: $\iint_{S} curl F \cdot dS=\iint_{C} F \cdot dr$; and $C$ refers to the boundary of the surface oriented counter-clockwise. Both the surfaces $H$ and $P$ have the same boundary: the circle $x^2+y^2=4$ So, Stokes' Theorem can be defined as: $\iint_{H} curl F \cdot dS=\iint_{P} curl F \cdot dS=\iint_{C} F \cdot dr$; and $C$ is the circle $x^2+y^2=4$ oriented counter-clockwise.
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